Optimal. Leaf size=261 \[ 3 a b^2 c x+\frac {b^3 d x}{2 f}+\frac {3}{2} a b^2 d x^2+\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {b^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {b^3 (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}+\frac {3 a^2 b d \text {PolyLog}\left (2,-e^{2 (e+f x)}\right )}{2 f^2}+\frac {b^3 d \text {PolyLog}\left (2,-e^{2 (e+f x)}\right )}{2 f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f} \]
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Rubi [A]
time = 0.24, antiderivative size = 261, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 9, integrand size = 18, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.500, Rules used = {3803, 3799,
2221, 2317, 2438, 3801, 3556, 3554, 8} \begin {gather*} \frac {a^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (e^{2 (e+f x)}+1\right )}{f}-\frac {3 a^2 b (c+d x)^2}{2 d}+\frac {3 a^2 b d \text {Li}_2\left (-e^{2 (e+f x)}\right )}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}+3 a b^2 c x+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}+\frac {3}{2} a b^2 d x^2+\frac {b^3 (c+d x) \log \left (e^{2 (e+f x)}+1\right )}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}-\frac {b^3 (c+d x)^2}{2 d}+\frac {b^3 d \text {Li}_2\left (-e^{2 (e+f x)}\right )}{2 f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}+\frac {b^3 d x}{2 f} \end {gather*}
Antiderivative was successfully verified.
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Rule 8
Rule 2221
Rule 2317
Rule 2438
Rule 3554
Rule 3556
Rule 3799
Rule 3801
Rule 3803
Rubi steps
\begin {align*} \int (c+d x) (a+b \tanh (e+f x))^3 \, dx &=\int \left (a^3 (c+d x)+3 a^2 b (c+d x) \tanh (e+f x)+3 a b^2 (c+d x) \tanh ^2(e+f x)+b^3 (c+d x) \tanh ^3(e+f x)\right ) \, dx\\ &=\frac {a^3 (c+d x)^2}{2 d}+\left (3 a^2 b\right ) \int (c+d x) \tanh (e+f x) \, dx+\left (3 a b^2\right ) \int (c+d x) \tanh ^2(e+f x) \, dx+b^3 \int (c+d x) \tanh ^3(e+f x) \, dx\\ &=\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}+\left (6 a^2 b\right ) \int \frac {e^{2 (e+f x)} (c+d x)}{1+e^{2 (e+f x)}} \, dx+\left (3 a b^2\right ) \int (c+d x) \, dx+b^3 \int (c+d x) \tanh (e+f x) \, dx+\frac {\left (3 a b^2 d\right ) \int \tanh (e+f x) \, dx}{f}+\frac {\left (b^3 d\right ) \int \tanh ^2(e+f x) \, dx}{2 f}\\ &=3 a b^2 c x+\frac {3}{2} a b^2 d x^2+\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {b^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}+\left (2 b^3\right ) \int \frac {e^{2 (e+f x)} (c+d x)}{1+e^{2 (e+f x)}} \, dx-\frac {\left (3 a^2 b d\right ) \int \log \left (1+e^{2 (e+f x)}\right ) \, dx}{f}+\frac {\left (b^3 d\right ) \int 1 \, dx}{2 f}\\ &=3 a b^2 c x+\frac {b^3 d x}{2 f}+\frac {3}{2} a b^2 d x^2+\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {b^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {b^3 (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}-\frac {\left (3 a^2 b d\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (e+f x)}\right )}{2 f^2}-\frac {\left (b^3 d\right ) \int \log \left (1+e^{2 (e+f x)}\right ) \, dx}{f}\\ &=3 a b^2 c x+\frac {b^3 d x}{2 f}+\frac {3}{2} a b^2 d x^2+\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {b^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {b^3 (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}+\frac {3 a^2 b d \text {Li}_2\left (-e^{2 (e+f x)}\right )}{2 f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}-\frac {\left (b^3 d\right ) \text {Subst}\left (\int \frac {\log (1+x)}{x} \, dx,x,e^{2 (e+f x)}\right )}{2 f^2}\\ &=3 a b^2 c x+\frac {b^3 d x}{2 f}+\frac {3}{2} a b^2 d x^2+\frac {a^3 (c+d x)^2}{2 d}-\frac {3 a^2 b (c+d x)^2}{2 d}-\frac {b^3 (c+d x)^2}{2 d}+\frac {3 a^2 b (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {b^3 (c+d x) \log \left (1+e^{2 (e+f x)}\right )}{f}+\frac {3 a b^2 d \log (\cosh (e+f x))}{f^2}+\frac {3 a^2 b d \text {Li}_2\left (-e^{2 (e+f x)}\right )}{2 f^2}+\frac {b^3 d \text {Li}_2\left (-e^{2 (e+f x)}\right )}{2 f^2}-\frac {b^3 d \tanh (e+f x)}{2 f^2}-\frac {3 a b^2 (c+d x) \tanh (e+f x)}{f}-\frac {b^3 (c+d x) \tanh ^2(e+f x)}{2 f}\\ \end {align*}
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Mathematica [A]
time = 2.22, size = 265, normalized size = 1.02 \begin {gather*} \frac {\cosh (e+f x) \left (b^3 f (c+d x)+\cosh ^2(e+f x) \left (-\left ((e+f x) \left (-3 a^2 b d (e+f x)-b^3 d (e+f x)+a^3 (-2 c f+d (e-f x))+3 a b^2 (-2 c f+d (e-f x))\right )\right )+2 b \left (3 a^2+b^2\right ) d (e+f x) \log \left (1+e^{-2 (e+f x)}\right )-2 b \left (-3 a b d+3 a^2 (d e-c f)+b^2 (d e-c f)\right ) \log (\cosh (e+f x))\right )-b \left (3 a^2+b^2\right ) d \cosh ^2(e+f x) \text {PolyLog}\left (2,-e^{-2 (e+f x)}\right )-\frac {1}{2} b^2 (b d+6 a f (c+d x)) \sinh (2 (e+f x))\right ) (a+b \tanh (e+f x))^3}{2 f^2 (a \cosh (e+f x)+b \sinh (e+f x))^3} \end {gather*}
Antiderivative was successfully verified.
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Maple [A]
time = 2.78, size = 459, normalized size = 1.76
method | result | size |
risch | \(c x \,a^{3}+\frac {3 b^{2} d a \ln \left (1+{\mathrm e}^{2 f x +2 e}\right )}{f^{2}}+\frac {2 b^{3} d e \ln \left ({\mathrm e}^{f x +e}\right )}{f^{2}}+\frac {3 a^{2} b d \polylog \left (2, -{\mathrm e}^{2 f x +2 e}\right )}{2 f^{2}}-\frac {6 b \,a^{2} d e x}{f}+\frac {6 b \,a^{2} d e \ln \left ({\mathrm e}^{f x +e}\right )}{f^{2}}+\frac {3 b \ln \left (1+{\mathrm e}^{2 f x +2 e}\right ) a^{2} d x}{f}+\frac {b^{3} \ln \left (1+{\mathrm e}^{2 f x +2 e}\right ) d x}{f}-\frac {6 b \,a^{2} c \ln \left ({\mathrm e}^{f x +e}\right )}{f}+\frac {3 b \,a^{2} c \ln \left (1+{\mathrm e}^{2 f x +2 e}\right )}{f}-\frac {6 b^{2} d a \ln \left ({\mathrm e}^{f x +e}\right )}{f^{2}}+\frac {b^{2} \left (6 a d f x \,{\mathrm e}^{2 f x +2 e}+2 b d f x \,{\mathrm e}^{2 f x +2 e}+6 a c f \,{\mathrm e}^{2 f x +2 e}+2 b c f \,{\mathrm e}^{2 f x +2 e}+6 a d f x +b d \,{\mathrm e}^{2 f x +2 e}+6 a c f +b d \right )}{f^{2} \left (1+{\mathrm e}^{2 f x +2 e}\right )^{2}}-\frac {3 b \,a^{2} d \,e^{2}}{f^{2}}+\frac {a^{3} d \,x^{2}}{2}-\frac {b^{3} d \,x^{2}}{2}+b^{3} c x -\frac {2 b^{3} d e x}{f}-\frac {3 a^{2} b d \,x^{2}}{2}+3 a^{2} b c x +3 a \,b^{2} c x +\frac {3 a \,b^{2} d \,x^{2}}{2}+\frac {b^{3} d \polylog \left (2, -{\mathrm e}^{2 f x +2 e}\right )}{2 f^{2}}-\frac {2 b^{3} c \ln \left ({\mathrm e}^{f x +e}\right )}{f}+\frac {b^{3} c \ln \left (1+{\mathrm e}^{2 f x +2 e}\right )}{f}-\frac {b^{3} d \,e^{2}}{f^{2}}\) | \(459\) |
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.54, size = 465, normalized size = 1.78 \begin {gather*} \frac {1}{2} \, a^{3} d x^{2} + b^{3} c {\left (x + \frac {e}{f} + \frac {\log \left (e^{\left (-2 \, f x - 2 \, e\right )} + 1\right )}{f} + \frac {2 \, e^{\left (-2 \, f x - 2 \, e\right )}}{f {\left (2 \, e^{\left (-2 \, f x - 2 \, e\right )} + e^{\left (-4 \, f x - 4 \, e\right )} + 1\right )}}\right )} + a^{3} c x - \frac {6 \, a b^{2} d x}{f} + \frac {3 \, a^{2} b c \log \left (\cosh \left (f x + e\right )\right )}{f} - {\left (3 \, a^{2} b d + b^{3} d\right )} x^{2} + \frac {3 \, a b^{2} d \log \left (e^{\left (2 \, f x + 2 \, e\right )} + 1\right )}{f^{2}} + \frac {12 \, a b^{2} c f + 6 \, {\left (c f^{2} + 2 \, d f\right )} a b^{2} x + 2 \, b^{3} d + {\left (3 \, a^{2} b d f^{2} + 3 \, a b^{2} d f^{2} + b^{3} d f^{2}\right )} x^{2} + {\left (6 \, a b^{2} c f^{2} x e^{\left (4 \, e\right )} + {\left (3 \, a^{2} b d f^{2} + 3 \, a b^{2} d f^{2} + b^{3} d f^{2}\right )} x^{2} e^{\left (4 \, e\right )}\right )} e^{\left (4 \, f x\right )} + 2 \, {\left ({\left (3 \, a^{2} b d f^{2} + 3 \, a b^{2} d f^{2} + b^{3} d f^{2}\right )} x^{2} e^{\left (2 \, e\right )} + 2 \, {\left (b^{3} d f + 3 \, {\left (c f^{2} + d f\right )} a b^{2}\right )} x e^{\left (2 \, e\right )} + {\left (6 \, a b^{2} c f + b^{3} d\right )} e^{\left (2 \, e\right )}\right )} e^{\left (2 \, f x\right )}}{2 \, {\left (f^{2} e^{\left (4 \, f x + 4 \, e\right )} + 2 \, f^{2} e^{\left (2 \, f x + 2 \, e\right )} + f^{2}\right )}} + \frac {{\left (3 \, a^{2} b d + b^{3} d\right )} {\left (2 \, f x \log \left (e^{\left (2 \, f x + 2 \, e\right )} + 1\right ) + {\rm Li}_2\left (-e^{\left (2 \, f x + 2 \, e\right )}\right )\right )}}{2 \, f^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [C] Result contains complex when optimal does not.
time = 0.47, size = 4628, normalized size = 17.73 \begin {gather*} \text {Too large to display} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \left (a + b \tanh {\left (e + f x \right )}\right )^{3} \left (c + d x\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\left (a+b\,\mathrm {tanh}\left (e+f\,x\right )\right )}^3\,\left (c+d\,x\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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